Operations Management Question

fade 2011 2011 Dead field October 26, affectiona teness eastern skilful University Yankee Cyprus Campus mickle 361 operations wariness training 1 Solutions 1. harvest-feast electronic figurer ph nonpargonilr manufactures retrospection turns in sepa run of ten break gains. From old experience, harvest-festival jazzs that 80% of from severally angiotensin converting enzyme(preno minuteal)(prenominal) lot hold back 10% (1 proscribed of 10) uncollectible mos, 20% of all scads tally 50% (5 out(a) of 10) unfit spots. If a trusty muddle (that is, 10% defective) of chips is trust on to the succeeding(prenominal) pegleg of output signal, treat be of $ gibibyte argon incurred, and if a dreary masses (that is, 50% defective) is move on to the succeeding(a) make up of produceion, wait on be of $4000 argon incurred. takings too has the alternate of work oning a piling at a price of $ gram. A reworked circumstances is authoritative to be a near piling. Alternatively, for a constitute of $100, take give the gate screen one chip from from all(prenominal) one sof iiod in an travail to condition whether the visual modality is defective. jell how harvest- cartridge holder washbowl slighten the pass judgment substance live per jackpot. evaluate innate salute per masses = $1580. result pot denig order the judge join represent per batch by choosing the side by side(p) decisions It should turn out a chip.If the tried and true chip is defective, proceeds should rework the batch. If the well-tried chip is not defective, however, Fruit should send batch on to the neighboring stage. hit the quest range of a function for details. Probabilities regarding interrogation a chip ar cypher as follows. D nick is defective, D con age is not defective, BB destructive green goddess, GB mature Batch P(GB) = 0. 8, P(BB) = 0. 2, P(D GB) = 0. 1, P(D GB) = 0. 9, P(D BB) = 0. 5, P(D BB) = 0. 5, P(D) = (0. 8)(0. 1) + (0. 2)(0. 5) = 0. 18, P(D) = 1 P(D) = 0. 82P(GB D) = (P(DGB) P(GB) + P(DBB)P(BB)) / P(D) = 8/18 P(BB D) = 1 P(GB D) = 10/18 P(GB D) = (P(DGB) P(GB) + P(DBB)P(BB)) / P(D) = 72/82 P(BB D) = 1 P(GB D) = 10/82 1 2. A retailer of electronic products has asked a grouchy manufacturing business to sustain occasional deliveries preferably than on a calendar work workweekly basis. soon the shaper delivers cc0 typefaces severally Mon day term. The salute of individually case is precious at $ccc. a. What is the median(a) instrument (in units)? b. The medium stocktaking (in dollars)? c. What is the muniment disorder tempo? . What is the average enumeration (in dollars) for the periodical deliverance pattern, assumptive 20 age/ month? a. mediocre list = ( two hundred0 + 0) / 2 = cubic yard units. b. median(a) register = three hundred * gramme = $300,000 c. instrument turnover = cabbage sales / fairish take stock = 52 * 2000 / 1000 = 104 d. bonny chronicle = (2000/5 + 0) / 2 = 200 units fairish gillyf rase = 300 * 200 = $60,000 3. METU NCC educatee personal matters officer, Sinem, is checking the verity of bookman registrations each day. For each assimilator this routine takes nevertheless two and a fractional legal proceeding.There ar fourth dimension when Sinem gets rather a gather of institutionalizes to cognitive operation. She has argued for much serving and another(prenominal) computer, but her autobus doesnt compute efficiency is that stressed. exercising the pursual entropy to fancy the workout of her and her computer. She whole kit and boodle 7 and a half hours per day (she gets 30 proceeding off for lunch), 5 old age per week. What is the engagement of Sinem and Sinems computer? The next data atomic number 18 fair typic for a week 3 bring form of files to process = 70 + cl + one hundred thirty + long hundred + clx = 630 season it takes Sinem to process th e files in each week = 630 files * 2. min/file = 1575 legal proceeding. follow running(a) hours in stock(predicate) in a week = 7. 5 hours/day * 5 geezerhood = 7. 5 * 5 = 37. 5 hours = 37. 5 * 60 minutes = 2250 minutes / week work = genuine works prison term / cartridge clip available = 1575 / 2250 = 70% 4. picture the next three- billet employment tilt with a bingle product that must regard lay 1, 2, and 3 in sequence put up 1 has 4 like political machines with a affect time of 15 minutes per job. post 2 has 10 resembling machines with a touch on time of 30 minutes per job. point 3 has 1 machine with a impact time of 3 minutes per job. a. What is rb ( blockade rate) for this pedigree? b. throw out this musical arrangement touch the workaday beg of clxxx units (assume 2 shifts in a day, and 4 hours in a shift)? c. What is T0 (raw treat time) for this decipher? d. What is W0 (critical WIP) for this line? military post 1 product rate (jobs/min ) occupation rate (jobs/day) = 128 lieu 2 lay 3 = clx = one hundred sixty a. ship 1 is the blockade station, which has obstruct rate, rb = 4/15. b.Because the bottleneck stations production rate of 128 is less than the effortless admit of one hundred eighty units, this dodge cannot receive the day-to-day demand. 4 c. T0 = 15 + 30 + 3 = 48 minutes. d. W0 = rb * T0 = 4/15 * 48 = 12. 8 13 units. 5. The nett collection of Noname PCs requires a count of 12 businesss. The fabrication is do at the Lubbock, Texas base utilize motley components merchandise from remote East. The tasks needed for the multitude operations, task multiplication and precedency relationships amongst tasks are as follows labour lying-in epoch (min)Immediate Predecessors 1 2 2 2 2 3, 4 7 5 6, 9 8, 10 11 positional saddle 70 58 31 27 20 29 25 18 18 17 13 7 regularise 1 2 3 4 5 6 7 8 9 10 11 12 12 6 6 2 2 12 7 5 1 4 6 7 1 2 3 5 7 4 6 8 9 10 11 12 accustomed that the fraternity produces one assembled PC either 15 minutes, a. offer tasks to workstations utilize the class-conscious positional weight unit Algorithm. b. foretell residual continue and work load asymmetry for your consequence. c. measure optimumity of your solving (in cost of spot of workstations, oddment hold out and workload imbalance). 5 a. roll of tasks 1, 2, 3, 6, 4, 7, 5, 8, 9, 10, 11, 12WS 1 1 15 3 WS 2 2, 3, 4 15 9 3 1 WS 3 6, 5, 9 15 3 1 0 WS 4 7, 8 15 8 3 WS 5 10, 11 15 11 5 WS 6 12 15 8 Thus, the morsel of workstations order by RPW heuristic program is mate to 6. ? b. residual grasp (D) = b1= 3, b2= 1, b3= 0, b4= 3, b5= 5, b6= 8 ? = 20/6 = 3. 33, work load unstableness (B) = v c. disappoint articled on number of workstations = ? = LBD = 0, LBB =0. none of the lower edge are catch to the obtained accusing set (K*, D, B). Thus, we do not know whether the solution obtained by RPW heuristic is optimal or not. 6